tag:blogger.com,1999:blog-6986082220402081615.post8761440020808481430..comments2023-04-24T08:10:28.755-07:00Comments on Math for Liberal Arts: Square root practice.Prof. Hubbardhttp://www.blogger.com/profile/16575880031145705761noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-6986082220402081615.post-45599791424379796602011-03-24T16:54:07.186-07:002011-03-24T16:54:07.186-07:00I get it now....I get it. :)I get it now....I get it. :)Unknownhttps://www.blogger.com/profile/17561929882440988680noreply@blogger.comtag:blogger.com,1999:blog-6986082220402081615.post-50815471749674988172011-03-22T19:39:18.864-07:002011-03-22T19:39:18.864-07:00What we were doing here is guess and check, but we...What we were doing here is guess and check, but we've learned in class a way to find any odd number 2a+1 as the difference between (a+1)^2 - a^2.Prof. Hubbardhttps://www.blogger.com/profile/16575880031145705761noreply@blogger.comtag:blogger.com,1999:blog-6986082220402081615.post-13741977754131088442011-03-22T16:59:30.928-07:002011-03-22T16:59:30.928-07:00but how are you finding the numbers (legs)? Is the...but how are you finding the numbers (legs)? Is their an easy way to figure out what those numbers are?Unknownhttps://www.blogger.com/profile/17561929882440988680noreply@blogger.comtag:blogger.com,1999:blog-6986082220402081615.post-59181390153575961772011-03-17T19:43:25.480-07:002011-03-17T19:43:25.480-07:001) Make a right triangle that will have two whole ...1) Make a right triangle that will have two whole number side lengths and one side with length of sqrt(7).<br /><br /><b>Answer: 4² - 3² = 7, so we can make a right triangle with legs of length 3 and sqrt(7) and hypotenuse 4.</b><br /><br><br /><br /><br />2) Make a right triangle that will have two whole number side lengths and one side with length of sqrt(18).<br /><br /><b>Answer: 3² + 3² = 18, so we can make a right triangle with legs of length 3 and 3 and hypotenuse of sqrt(18).</b><br /><br><br /><br />3) Make TWO different right triangles that will have two whole number side lengths and one side with length of sqrt(20).<br /><br /><br /><b>Answer: 4² + 2² = 20, so we can make a right triangle with legs of length 4 and 2 and hypotenuse of sqrt(20).</b><br /><br /><b>Answer: 6² - 4² = 20, so we can make a right triangle with hypotenuse of length 6 and legs of length 4 and sqrt(20).</b><br /><br><br /><br /><br />4) Make TWO different right triangles that will have two whole number side lengths and one side with length of sqrt(50).<br /><br /><b>Answer: 7² + 1² = 50, so we can make a right triangle with legs of length 7 and 1 and hypotenuse of sqrt(50).</b><br /><br /><b>Answer: 5² + 5² = 50, so we can make a right triangle with legs of length 5 and 5 and hypotenuse of sqrt(50).</b><br /><br>Prof. Hubbardhttps://www.blogger.com/profile/16575880031145705761noreply@blogger.com